Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-18 19:57Z
10z² + 2z + 2 = 0
λ = h/p
\frac{12}{6} \sum_{i=1}^{n} i^{2}
405K
\frac{5}{1} \sum_{i=1}^{n} i^{2}
d/dβ [β^2] = 2β^1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
139K
det| 9 4 ; 1 10 | = 86
304K
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
78K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
3ω² + 5ω + 3 = 0