Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:26Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
10ω² + 6ω + 2 = 0
det| 9 4 ; 1 10 | = 86
366K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
224K
12z² + 3z + 1 = 0
\frac{3}{1} \sum_{i=1}^{n} i^{2}
det| 2 4 ; 4 3 | = -10
273K