Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 19:04Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
97K
12γ² + 5γ + 2 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
366K
λ = h/p
det| 9 4 ; 1 10 | = 86
224K
det| 7 6 ; 6 8 | = 20
\frac{11}{1} \sum_{i=1}^{n} i^{2}
\lim_{n\to 0} \frac{\sin n}{n} = 1
e^{i\pi} + 1 = 0