Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-18 21:22Z
d/dβ [β^5] = 5β^4
8n² + 1n + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
311K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
390K
\lim_{α\to 0} \frac{\sin α}{α} = 1
det| 7 4 ; 4 8 | = 40
139K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
304K
7θ² + 7θ + 2 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
78K
det| 9 8 ; 3 10 | = 66
221K