Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 20:56Z
det| 6 5 ; 3 7 | = 27
det| 5 6 ; 7 6 | = -12
129K
∑_{k=1}^{n} k = n(n+1)/2
97K
d/dn [n^11] = 11n^10
det| 6 6 ; 2 7 | = 30
CH₄ + 2O₂ → CO₂ + 2H₂O
224K
det| 4 2 ; 1 5 | = 18
452K
E = mc²
det| 9 4 ; 1 10 | = 86
155K
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
273K