Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-18 21:20Z
d/dβ [β^5] = 5β^4
8n² + 1n + 1 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
405K
det| 7 1 ; 7 8 | = 49
311K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-θ²) dθ = √π / 2
390K
\lim_{α\to 0} \frac{\sin α}{α} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
139K
7θ² + 7θ + 2 = 0
1θ² + 2θ + 3 = 0