Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:24Z
ω = 2πf
det| 3 9 ; 1 4 | = 3
129K
10ω² + 6ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
366K
ω = 2πf
Fe₂O₃ + 3CO → 2Fe + 3CO₂
224K
∑_{k=1}^{n} k = n(n+1)/2
452K
12z² + 3z + 1 = 0
det| 5 2 ; 3 6 | = 24
155K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
33K
\frac{3}{1} \sum_{i=1}^{n} i^{2}