Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 13:06Z
12t² + 1t + 5 = 0
d/dx [x^11] = 11x^10
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
398K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
271K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{3}{2} \sum_{i=1}^{n} i^{2}
396K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
346K
∑_{k=1}^{n} k = n(n+1)/2
24K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
234K