Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:20Z
ω = 2πf
∫₀^∞ e^(-z²) dz = √π / 2
97K
10ω² + 6ω + 2 = 0
det| 7 4 ; 4 8 | = 40
354K
∑_{k=1}^{n} k = n(n+1)/2
366K
ω = 2πf
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
452K
12z² + 3z + 1 = 0
det| 2 7 ; 7 3 | = -43
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