Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:21Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
10ω² + 6ω + 2 = 0
det| 7 4 ; 4 8 | = 40
354K
ω = 2πf
det| 5 2 ; 3 6 | = 24
224K
∫₀^∞ e^(-θ²) dθ = √π / 2
452K
12z² + 3z + 1 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
155K