Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:13Z
ω = 2πf
\frac{12}{7} \sum_{i=1}^{n} i^{2}
129K
10ω² + 6ω + 2 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
366K
ω = 2πf
\binom{n}{k} = \frac{n!}{k!(n-k)!}
224K
12z² + 3z + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
33K
\frac{3}{1} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
273K
det| 3 9 ; 1 4 | = 3
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