Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 12:54Z
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\frac{10}{8} \sum_{i=1}^{n} i^{2}
det| 5 9 ; 7 6 | = -33
354K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
224K
1y² + 8y + 3 = 0
\lim_{y\to 0} \frac{\sin y}{y} = 1
155K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
33K
\frac{7}{9} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
11y² + 6y + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃