Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 22:09Z
\frac{6}{4} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
129K
∂α/∂ω = 9α
det| 7 4 ; 4 8 | = 40
354K
det| 7 1 ; 7 8 | = 49
366K
\frac{4}{6} \sum_{i=1}^{n} i^{2}
det| 3 1 ; 7 4 | = 5
155K
∑_{k=1}^{n} k = n(n+1)/2
33K