Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 22:21Z
\frac{6}{4} \sum_{i=1}^{n} i^{2}
∂α/∂ω = 9α
AgNO₃ + NaCl → AgCl↓ + NaNO₃
366K
\frac{4}{6} \sum_{i=1}^{n} i^{2}
ΔS ≥ 0
F = G m₁m₂ / r²
det| 7 4 ; 4 8 | = 40
96K
\frac{8}{6} \sum_{i=1}^{n} i^{2}
273K
∇ × E = −∂B/∂t
λ = h/p