Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 05:16Z
det| 11 5 ; 5 12 | = 107
det| 9 4 ; 1 10 | = 86
369K
∑_{k=1}^{n} k = n(n+1)/2
133K
d/dz [z^3] = 3z^2
10θ² + 5θ + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
271K
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
396K
∑_{k=1}^{n} k = n(n+1)/2
346K