Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 06:11Z
9ω² + 4ω + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
369K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 7 4 ; 4 8 | = 40
264K
det| 10 5 ; 5 11 | = 85
ΔS ≥ 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
98K
∇²θ = 0
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
126K
E = mc²