Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:07Z
ω = 2πf
\binom{n}{k} = \frac{n!}{k!(n-k)!}
129K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
97K
10ω² + 6ω + 2 = 0
ω = 2πf
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
224K
12z² + 3z + 1 = 0
det| 5 7 ; 2 6 | = 16
155K
\frac{3}{1} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
96K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
273K
12t² + 9t + 1 = 0