Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 13:10Z
12t² + 1t + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
369K
det| 6 6 ; 3 7 | = 24
133K
d/dx [x^11] = 11x^10
det| 7 4 ; 4 8 | = 40
398K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
396K