Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 05:54Z
det| 11 5 ; 5 12 | = 107
det| 7 4 ; 4 8 | = 40
369K
∑_{k=1}^{n} k = n(n+1)/2
133K
d/dz [z^3] = 3z^2
10θ² + 5θ + 4 = 0
det| 7 9 ; 1 8 | = 47
404K
det| 5 2 ; 3 6 | = 24
396K
∑_{k=1}^{n} k = n(n+1)/2
346K