Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:17Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
10ω² + 6ω + 2 = 0
det| 4 8 ; 3 5 | = -4
366K
ω = 2πf
det| 5 6 ; 7 6 | = -12
224K
12z² + 3z + 1 = 0
det| 9 1 ; 7 10 | = 83
155K
det| 7 4 ; 4 8 | = 40
33K
\frac{3}{1} \sum_{i=1}^{n} i^{2}
det| 3 9 ; 1 4 | = 3
273K
12t² + 9t + 1 = 0