Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:23Z
ω = 2πf
10ω² + 6ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
366K
ω = 2πf
det| 9 4 ; 1 10 | = 86
224K
det| 1 1 ; 5 2 | = -3
452K
12z² + 3z + 1 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
155K
det| 2 7 ; 7 3 | = -43
33K
\frac{3}{1} \sum_{i=1}^{n} i^{2}