Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 12:55Z
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-r²) dr = √π / 2
129K
\frac{10}{8} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-ψ²) dψ = √π / 2
366K
E = mc²
det| 6 6 ; 2 7 | = 30
452K
1y² + 8y + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
245K