Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 01:24Z
8y² + 4y + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
129K
∇²ψ = 0
11γ² + 4γ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
224K
CH₄ + 2O₂ → CO₂ + 2H₂O
452K
d/dβ [β^9] = 9β^8
det| 7 4 ; 4 8 | = 40
33K
λ = h/p
∇²z = 0