Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:27Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
det| 7 4 ; 4 8 | = 40
97K
10ω² + 6ω + 2 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
354K
ω = 2πf
∫₀^∞ e^(-α²) dα = √π / 2
224K
12z² + 3z + 1 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
155K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
273K