Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 01:23Z
8y² + 4y + 1 = 0
∇²ψ = 0
∑_{k=1}^{n} k = n(n+1)/2
354K
11γ² + 4γ + 3 = 0
d/dβ [β^9] = 9β^8
∑_{k=1}^{n} k = n(n+1)/2
155K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
33K
CH₄ + 2O₂ → CO₂ + 2H₂O
273K