Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 13:29Z
12t² + 1t + 5 = 0
∫₀^∞ e^(-α²) dα = √π / 2
133K
d/dx [x^11] = 11x^10
\binom{n}{k} = \frac{n!}{k!(n-k)!}
398K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dα [α^3] = 3α^2
det| 9 4 ; 1 10 | = 86
346K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
24K
\frac{12}{6} \sum_{i=1}^{n} i^{2}
126K