Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:27Z
ω = 2πf
det| 4 4 ; 5 5 | = 0
129K
det| 5 2 ; 3 6 | = 24
97K
10ω² + 6ω + 2 = 0
det| 7 4 ; 4 8 | = 40
354K
CH₄ + 2O₂ → CO₂ + 2H₂O
366K
ω = 2πf
12z² + 3z + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
155K
∑_{k=1}^{n} k = n(n+1)/2
33K