Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 19:07Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
12γ² + 5γ + 2 = 0
λ = h/p
∫₀^∞ e^(-θ²) dθ = √π / 2
224K
det| 7 6 ; 6 8 | = 20
\frac{11}{1} \sum_{i=1}^{n} i^{2}
\lim_{n\to 0} \frac{\sin n}{n} = 1
e^{i\pi} + 1 = 0
8α² + 7α + 5 = 0
∂α/∂β = 6α