Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 19:52Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{2}{2} \sum_{i=1}^{n} i^{2}
129K
12γ² + 5γ + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
366K
λ = h/p
det| 7 4 ; 4 8 | = 40
224K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
452K
∫₀^∞ e^(-θ²) dθ = √π / 2
96K
\frac{3}{2} \sum_{i=1}^{n} i^{2}
273K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
245K