Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 08:18Z
∇²β = 0
\frac{2}{5} \sum_{i=1}^{n} i^{2}
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
271K
6γ² + 6γ + 2 = 0
∫₀^∞ e^(-θ²) dθ = √π / 2
98K
det| 11 7 ; 1 12 | = 125
det| 9 1 ; 1 10 | = 89
det| 3 8 ; 3 4 | = -12
9γ² + 6γ + 0 = 0
N₂ + 3H₂ ⇌ 2NH₃