Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 16:24Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-x²) dx = √π / 2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
354K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
det| 7 4 ; 4 8 | = 40
224K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
452K
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
155K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
96K
∑_{k=1}^{n} k = n(n+1)/2
273K
F = G m₁m₂ / r²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
245K