Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 13:02Z
12t² + 1t + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
369K
d/dx [x^11] = 11x^10
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 3 3 ; 4 4 | = 0
271K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 9 4 ; 1 10 | = 86
98K
d/dα [α^3] = 3α^2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
346K
∫₀^∞ e^(-ψ²) dψ = √π / 2
24K
∑_{k=1}^{n} k = n(n+1)/2