Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 06:47Z
9ω² + 4ω + 4 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 10 5 ; 5 11 | = 85
det| 9 4 ; 1 10 | = 86
404K
∑_{k=1}^{n} k = n(n+1)/2
271K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
98K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
396K
∇²θ = 0
E = mc²
ω = 2πf
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}