Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 01:03Z
8y² + 4y + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
129K
∇²ψ = 0
det| 9 4 ; 1 10 | = 86
354K
11γ² + 4γ + 3 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
452K
d/dβ [β^9] = 9β^8
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
96K
d/dα [α^8] = 8α^7
∇²z = 0