Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 13:06Z
12t² + 1t + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
133K
d/dx [x^11] = 11x^10
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
98K
d/dα [α^3] = 3α^2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
346K
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-n²) dn = √π / 2
det| 4 1 ; 3 5 | = 17