Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:24Z
ω = 2πf
10ω² + 6ω + 2 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
366K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
224K
det| 6 6 ; 2 7 | = 30
452K
12z² + 3z + 1 = 0
det| 9 4 ; 1 10 | = 86
33K
det| 7 6 ; 1 8 | = 50
245K