Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:07Z
ω = 2πf
10ω² + 6ω + 2 = 0
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
224K
12z² + 3z + 1 = 0
det| 10 1 ; 6 11 | = 104
33K
\frac{3}{1} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
96K
det| 1 1 ; 5 2 | = -3
245K
det| 3 1 ; 7 4 | = 5
213K