Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:43Z
ω = 2πf
10ω² + 6ω + 2 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
354K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
366K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
224K
12z² + 3z + 1 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
96K
det| 11 9 ; 0 12 | = 132
273K
det| 7 4 ; 4 8 | = 40
245K