Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:28Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
det| 7 4 ; 4 8 | = 40
97K
10ω² + 6ω + 2 = 0
ω = 2πf
12z² + 3z + 1 = 0
∫₀^∞ e^(-α²) dα = √π / 2
33K
\frac{3}{1} \sum_{i=1}^{n} i^{2}
11z² + 7z + 1 = 0