Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-18 21:20Z
d/dβ [β^5] = 5β^4
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
192K
8n² + 1n + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
311K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
390K
\lim_{α\to 0} \frac{\sin α}{α} = 1
det| 1 4 ; 0 2 | = 2
139K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
479K
det| 6 6 ; 3 7 | = 24
78K