Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-20 05:52Z
det| 11 5 ; 5 12 | = 107
∫₀^∞ e^(-z²) dz = √π / 2
133K
d/dz [z^3] = 3z^2
10θ² + 5θ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
271K
N₂ + 3H₂ ⇌ 2NH₃
det| 2 7 ; 7 3 | = -43
98K
CH₄ + 2O₂ → CO₂ + 2H₂O
24K
∑_{k=1}^{n} k = n(n+1)/2
234K