Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 03:26Z
det| 7 9 ; 6 8 | = 2
∑_{k=1}^{n} k = n(n+1)/2
129K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-r²) dr = √π / 2
354K
6n² + 6n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
452K
∂r/∂β = 1r
CaCO₃ → CaO + CO₂