Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 12:50Z
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-γ²) dγ = √π / 2
97K
\frac{10}{8} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-θ²) dθ = √π / 2
354K
det| 2 5 ; 2 3 | = -4
366K
E = mc²
det| 8 4 ; 7 9 | = 44
224K
1y² + 8y + 3 = 0
\frac{7}{9} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
96K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 1 4 ; 0 2 | = 2
213K
AgNO₃ + NaCl → AgCl↓ + NaNO₃