Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 19:58Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
12γ² + 5γ + 2 = 0
λ = h/p
∫₀^∞ e^(-θ²) dθ = √π / 2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 7 6 ; 6 8 | = 20
\frac{11}{1} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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d/dy [y^11] = 11y^10
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