Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 20:35Z
det| 6 5 ; 3 7 | = 27
det| 7 4 ; 4 8 | = 40
129K
d/dn [n^11] = 11n^10
CH₄ + 2O₂ → CO₂ + 2H₂O
366K
det| 6 6 ; 2 7 | = 30
E = mc²
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
273K