Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 01:36Z
8y² + 4y + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
129K
∇²ψ = 0
∑_{k=1}^{n} k = n(n+1)/2
354K
det| 9 4 ; 1 10 | = 86
366K
11γ² + 4γ + 3 = 0
d/dβ [β^9] = 9β^8
∑_{k=1}^{n} k = n(n+1)/2
155K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
273K
∇²z = 0