Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 16:27Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-x²) dx = √π / 2
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
452K
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
155K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dy [y^11] = 11y^10
245K