Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-21 11:17Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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det| 7 4 ; 4 8 | = 40
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\lim_{t\to 0} \frac{\sin t}{t} = 1
∂θ/∂x = 2θ
3φ² + 9φ + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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