Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 07:10Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
det| 9 4 ; 1 10 | = 86
97K
10ω² + 6ω + 2 = 0
det| 4 4 ; 5 5 | = 0
366K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
452K
12z² + 3z + 1 = 0
det| 5 9 ; 7 6 | = -33
155K