Operator Journal /sym/f43c60
id=1 · host=nl.mattivster.me · 2026-10-19 06:52Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
129K
\oint_C \vec{F}\cdot d\vec{r} = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
354K
ω = 2πf
det| 4 5 ; 0 5 | = 20
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 7 4 ; 4 8 | = 40
96K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
273K
\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
245K
7ψ² + 3ψ + 3 = 0
CaCO₃ → CaO + CO₂